What is (y^{-1})/(2w^{-5)} ?

The solution to (y^{-1})/(2w^{-5)} is (w^5)/(2y)

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simplify (y^{-1})/(2w^{-5)}

simplify

\frac{y ^{- 1}}{2 w ^{- 5}}

\frac{w ^{5}}{2 y}

Solution steps

\frac{y ^{- 1}}{2 w ^{- 5}}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

y^{- 1} = \frac{1}{y}

= \frac{\frac{1}{y}}{2 w ^{- 5}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{y \cdot 2 w ^{- 5}}

Simplify

y \cdot 2 w^{- 5} : \frac{2 y}{w ^{5}}

= \frac{1}{\frac{2 y}{w ^{5}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{w ^{5}}{2 y}

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