What is ((9x^{-2})/(xy))^{-2} ?

The solution to ((9x^{-2})/(xy))^{-2} is (x^6y^2)/(81)

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simplify ((9x^{-2})/(xy))^{-2}

simplify

(\frac{9 x ^{- 2}}{x y})^{- 2}

\frac{x ^{6} y ^{2}}{81}

Solution steps

(\frac{9 x ^{- 2}}{x y})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{9 x ^{- 2}}{x y})^{- 2} = \frac{1}{( \frac{9 x ^{- 2}}{x y} ) ^{2}}

= \frac{1}{( \frac{9 x ^{- 2}}{x y} ) ^{2}}

Simplify

(\frac{9 x ^{- 2}}{x y})^{2} : \frac{81}{x ^{6} y ^{2}}

= \frac{1}{\frac{81}{x ^{6} y ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{6} y ^{2}}{81}

6 x^{3}

x^{2} - 2 x - 8 x - 10

8 x^{2} + 14 x + 5

(\frac{49}{64})^{\frac{3}{2}}

2 x^{3} + 2 x^{2}

What is ((9x^{-2})/(xy))^{-2} ?
The solution to ((9x^{-2})/(xy))^{-2} is (x^6y^2)/(81)