What is expand (2x-1)(3x^2-3x+4) ?

The solution to expand (2x-1)(3x^2-3x+4) is 6x^3-9x^2+11x-4

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expand (2x-1)(3x^2-3x+4)

expand

(2 x - 1) (3 x^{2} - 3 x + 4)

6 x^{3} - 9 x^{2} + 11 x - 4

Solution steps

(2 x - 1) (3 x^{2} - 3 x + 4)

Distribute parentheses

= 2 x \cdot 3 x^{2} + 2 x (- 3 x) + 2 x \cdot 4 - 1 \cdot 3 x^{2} - 1 \cdot (- 3 x) - 1 \cdot 4

Simplify

2 x \cdot 3 x^{2} + 2 x (- 3 x) + 2 x \cdot 4 - 1 \cdot 3 x^{2} - 1 \cdot (- 3 x) - 1 \cdot 4 : 6 x^{3} - 9 x^{2} + 11 x - 4

= 6 x^{3} - 9 x^{2} + 11 x - 4

∣ 1 ∣ - 4

(30 - 2 x) (18 - 2 x) (x)

\frac{2 a b ^{5}}{2 a ^{- 2}}

81 r^{2} - 16 t^{2}

What is expand (2x-1)(3x^2-3x+4) ?
The solution to expand (2x-1)(3x^2-3x+4) is 6x^3-9x^2+11x-4