What are the solutions to the equation 2X^2-72=0 ?

The solutions to the equation 2X^2-72=0 are X=6,X=-6

Find the zeros of 2X^2-72=0

The zeros of 2X^2-72=0 are X=6,X=-6

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2 X^{2} - 72 = 0

X = 6, X = - 6

Solution steps

2 X^{2} - 72 = 0

Move

72

to the right side

2 X^{2} = 72

Divide both sides by

2

X^{2} = 36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

X = 36, X = - 36

36 = 6

- 36 = - 6

X = 6, X = - 6

\frac{7 !}{5 ! ( 2 ! )}

\frac{x}{x + 1} < 5

3 x + 5 \geq 41

(\frac{6}{2})^{2}

(3 - 4 i) (2 + 3 i)

What are the solutions to the equation 2X^2-72=0 ?
The solutions to the equation 2X^2-72=0 are X=6,X=-6
Find the zeros of 2X^2-72=0
The zeros of 2X^2-72=0 are X=6,X=-6