What are the solutions to the equation -2x^2+16x+1=0 ?

The solutions to the equation -2x^2+16x+1=0 are x=-(-8+sqrt(66))/2 ,x=(8+sqrt(66))/2

Find the zeros of -2x^2+16x+1=0

The zeros of -2x^2+16x+1=0 are x=-(-8+sqrt(66))/2 ,x=(8+sqrt(66))/2

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- 2 x^{2} + 16 x + 1 = 0

x = - \frac{- 8 + 66}{2}, x = \frac{8 + 66}{2}

Decimal Notation

x = - 0.06201 \dots, x = 8.06201 \dots

Solution steps

- 2 x^{2} + 16 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 2 ) \cdot 1}{2 ( - 2 )}

1 6^{2} - 4 (- 2) \cdot 1 = 266

x_{1, 2} = \frac{- 16 \pm 2 66}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 16 + 2 66}{2 ( - 2 )}, x_{2} = \frac{- 16 - 2 66}{2 ( - 2 )}

x = \frac{- 16 + 2 66}{2 ( - 2 )} : - \frac{- 8 + 66}{2}

x = \frac{- 16 - 2 66}{2 ( - 2 )} : \frac{8 + 66}{2}

The solutions to the quadratic equation are:

x = - \frac{- 8 + 66}{2}, x = \frac{8 + 66}{2}

5 ∣ x - 3 ∣ + 4 > 14

5 (9.8) (60) - 25 (9.8) e^{- \frac{60}{5}}

- 20 - 13 m - 17 m = 18 - 11 m

3 - \frac{3}{2}

(x - 2)^{2} = x^{2}

What are the solutions to the equation -2x^2+16x+1=0 ?
The solutions to the equation -2x^2+16x+1=0 are x=-(-8+sqrt(66))/2 ,x=(8+sqrt(66))/2
Find the zeros of -2x^2+16x+1=0
The zeros of -2x^2+16x+1=0 are x=-(-8+sqrt(66))/2 ,x=(8+sqrt(66))/2