What is (3-i)+(-2+4i) ?

The solution to (3-i)+(-2+4i) is 1+3i

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simplify (3-i)+(-2+4i)

simplify

(3 - i) + (- 2 + 4 i)

1 + 3 i

Solution steps

(3 - i) + (- 2 + 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (3 - 2) + (- 1 + 4) i

Simplify

(3 - 2) + (- 1 + 4) i : 1 + 3 i

= 1 + 3 i

\frac{3}{2} - \frac{1}{16}

16 a^{2}

- 2 - \frac{4}{3}

- 1 (x)

- 1 - 3 i