What is the answer to 2[7-5(1-n)]+8n=-16+3[6(n+1)-3n] ?

The answer to 2[7-5(1-n)]+8n=-16+3[6(n+1)-3n] is n=-2/9

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2[7-5(1-n)]+8n=-16+3[6(n+1)-3n]

2 [7 - 5 (1 - n)] + 8 n = - 16 + 3 [6 (n + 1) - 3 n]

n = - \frac{2}{9}

Solution steps

2 [7 - 5 (1 - n)] + 8 n = - 16 + 3 [6 (n + 1) - 3 n]

Expand

2 (7 - 5 (1 - n)) + 8 n : 18 n + 4

Expand

- 16 + 3 (6 (n + 1) - 3 n) : 9 n + 2

18 n + 4 = 9 n + 2

Move

4

to the right side

18 n = 9 n - 2

Move

9 n

to the left side

9 n = - 2

Divide both sides by

9

n = - \frac{2}{9}

x^{4} \leq x^{2}

2 (4 x + 3) = 10 x - 2

\frac{7}{12} + \frac{45}{4}

2 y + 3 > - 7

32 x^{5} - 200 x^{3} + 4 x^{2} - 25

What is the answer to 2[7-5(1-n)]+8n=-16+3[6(n+1)-3n] ?
The answer to 2[7-5(1-n)]+8n=-16+3[6(n+1)-3n] is n=-2/9
Solve for n: 2[7-5(1-n)]+8n=-16+3[6(n+1)-3n]
The solution is n=-2/9