What are the solutions to the equation x^2-8x+10=0 ?

The solutions to the equation x^2-8x+10=0 are x=4+sqrt(6),x=4-sqrt(6)

Find the zeros of x^2-8x+10=0

The zeros of x^2-8x+10=0 are x=4+sqrt(6),x=4-sqrt(6)

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x^{2} - 8 x + 10 = 0

x = 4 + 6, x = 4 - 6

Solution steps

x^{2} - 8 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 10 = 26

x_{1, 2} = \frac{- ( - 8 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 6}{2 \cdot 1} : 4 + 6

x = \frac{- ( - 8 ) - 2 6}{2 \cdot 1} : 4 - 6

The solutions to the quadratic equation are:

x = 4 + 6, x = 4 - 6

7 x^{2} + 6 = 0

5 x + 7 = 12

∣ 2 x - 5 ∣ \leq 9

(x^{2} - y^{2}) - ((x + y) (x - y)) + 3 x^{2}

x^{2} + x - 6 < 0

What are the solutions to the equation x^2-8x+10=0 ?
The solutions to the equation x^2-8x+10=0 are x=4+sqrt(6),x=4-sqrt(6)
Find the zeros of x^2-8x+10=0
The zeros of x^2-8x+10=0 are x=4+sqrt(6),x=4-sqrt(6)