What is factor 64y^6+27x^9 ?

The solution to factor 64y^6+27x^9 is (4y^2+3x^3)(16y^4-12y^2x^3+9x^6)

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factor 64y^6+27x^9

factor

64 y^{6} + 27 x^{9}

(4 y^{2} + 3 x^{3}) (16 y^{4} - 12 y^{2} x^{3} + 9 x^{6})

Solution steps

64 y^{6} + 27 x^{9}

Apply exponent rules

= (4 y^{2})^{3} + (3 x^{3})^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(4 y^{2})^{3} + (3 x^{3})^{3} = (4 y^{2} + 3 x^{3}) ((4 y^{2})^{2} - 4 y^{2} \cdot 3 x^{3} + (3 x^{3})^{2})

= (4 y^{2} + 3 x^{3}) ((4 y^{2})^{2} - 4 y^{2} \cdot 3 x^{3} + (3 x^{3})^{2})

Simplify

(4 y^{2})^{2} - 4 y^{2} \cdot 3 x^{3} + (3 x^{3})^{2} : 16 y^{4} - 12 y^{2} x^{3} + 9 x^{6}

= (4 y^{2} + 3 x^{3}) (16 y^{4} - 12 y^{2} x^{3} + 9 x^{6})

\frac{1}{6} \cdot \frac{2}{5}

e^{t} \cdot (- e^{- t})

(x - 5 y)^{3}

9 x^{2} - 36 x + 36

m x^{m - 2} (m - 1)

What is factor 64y^6+27x^9 ?
The solution to factor 64y^6+27x^9 is (4y^2+3x^3)(16y^4-12y^2x^3+9x^6)