What are the solutions to the equation x^2+8x+12=0 ?

The solutions to the equation x^2+8x+12=0 are x=-2,x=-6

Find the zeros of x^2+8x+12=0

The zeros of x^2+8x+12=0 are x=-2,x=-6

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x^{2} + 8 x + 12 = 0

x = - 2, x = - 6

Solution steps

x^{2} + 8 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 12 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 1}, x_{2} = \frac{- 8 - 4}{2 \cdot 1}

x = \frac{- 8 + 4}{2 \cdot 1} : - 2

x = \frac{- 8 - 4}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 2, x = - 6

6 x^{2} + x - 15

s^{3} + 6 s^{2} + 11 s + 6

x^{4} - 3 x^{3} + 3 x^{2} - x

4 x^{2} - 9 = 135

z^{2} - 30 = 13 z

What are the solutions to the equation x^2+8x+12=0 ?
The solutions to the equation x^2+8x+12=0 are x=-2,x=-6
Find the zeros of x^2+8x+12=0
The zeros of x^2+8x+12=0 are x=-2,x=-6