What is factor x^4-4x^3+7x^2-16x+12 ?

The solution to factor x^4-4x^3+7x^2-16x+12 is (x-1)(x-3)(x^2+4)

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factor x^4-4x^3+7x^2-16x+12

factor

x^{4} - 4 x^{3} + 7 x^{2} - 16 x + 12

(x - 1) (x - 3) (x^{2} + 4)

Solution steps

x^{4} - 4 x^{3} + 7 x^{2} - 16 x + 12

Use the rational root theorem

= (x - 1) \frac{x ^{4} - 4 x ^{3} + 7 x ^{2} - 16 x + 12}{x - 1}

\frac{x ^{4} - 4 x ^{3} + 7 x ^{2} - 16 x + 12}{x - 1} = x^{3} - 3 x^{2} + 4 x - 12

= (x - 1) (x^{3} - 3 x^{2} + 4 x - 12)

Factor

x^{3} - 3 x^{2} + 4 x - 12 : (x - 3) (x^{2} + 4)

= (x - 1) (x - 3) (x^{2} + 4)

2 x^{2} - 2 x + 2

x^{2} + y^{2}

(x - 3) - 3

5.2 \cdot 1 0^{3}

\frac{6 m ^{2} n ^{3}}{3 m}

What is factor x^4-4x^3+7x^2-16x+12 ?
The solution to factor x^4-4x^3+7x^2-16x+12 is (x-1)(x-3)(x^2+4)