What is (sqrt(-10^2-4))/(-10-2) ?

The solution to (sqrt(-10^2-4))/(-10-2) is -(sqrt(13))/(3sqrt(2))i

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simplify (sqrt(-10^2-4))/(-10-2)

simplify

\frac{- 1 0 ^{2} - 4}{- 10 - 2}

- \frac{13}{3 2} i

Solution steps

\frac{- 1 0 ^{2} - 4}{- 10 - 2}

- 1 0^{2} - 4 = 226 i

= \frac{2 26 i}{- 10 - 2}

Subtract the numbers:

- 10 - 2 = - 12

= \frac{2 26 i}{- 12}

Factor the number:

12 = 2 \cdot 6

= \frac{2 26 i}{- 2 \cdot 6}

Cancel the common factor:

2

= \frac{26 i}{- 6}

Factor the number:

6 = 2 \cdot 3

= \frac{26 i}{- 2 \cdot 3}

Factor

26 : 213

= \frac{2 13 i}{- 2 \cdot 3}

Apply radical rule:

a = a a

2 = 22

= \frac{2 13 i}{- 2 2 \cdot 3}

Cancel the common factor:

2

= \frac{13 i}{- 2 \cdot 3}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{13 i}{2 \cdot 3}

= - \frac{13 i}{3 2}

Rewrite in standard complex form:

- \frac{13}{3 2} i

= - \frac{13}{3 2} i

2^{3} 2^{5}

- 18 - (- 5)

100 p^{2} - 20 p + 4

\frac{0}{9 - 0 ^{2}}

3 m^{2} \cdot 2 m

What is (sqrt(-10^2-4))/(-10-2) ?
The solution to (sqrt(-10^2-4))/(-10-2) is -(sqrt(13))/(3sqrt(2))i