What is (6+2i)^2-(1-5i) ?

The solution to (6+2i)^2-(1-5i) is 31+29i

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simplify (6+2i)^2-(1-5i)

simplify

(6 + 2 i)^{2} - (1 - 5 i)

31 + 29 i

Solution steps

(6 + 2 i)^{2} - (1 - 5 i)

(6 + 2 i)^{2} = 24 i + 32

- (1 - 5 i) = - 1 - (- 5) i

= 24 i + 32 - 1 - (- 5) i

Group like terms

= 24 i - (- 5) i + 32 - 1

Add similar elements:

24 i - (- 5) i = 29 i

= 29 i + 32 - 1

Subtract the numbers:

32 - 1 = 31

= 29 i + 31

Rewrite in standard complex form:

31 + 29 i

= 31 + 29 i

\frac{100}{250}

3 \frac{6}{7}

8 x^{3} - x^{2} - 9 x^{5} + 10

\frac{3}{5} + \frac{9}{10}

4 r + 4 y - 8