What is factor y^2+4y-5 ?

The solution to factor y^2+4y-5 is (y-1)(y+5)

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factor y^2+4y-5

factor

y^{2} + 4 y - 5

(y - 1) (y + 5)

Solution steps

y^{2} + 4 y - 5

Break the expression into groups

= (y^{2} - y) + (5 y - 5)

Factor out

y

from

y^{2} - y : y (y - 1)

Factor out

5

from

5 y - 5 : 5 (y - 1)

= y (y - 1) + 5 (y - 1)

Factor out common term

y - 1

= (y - 1) (y + 5)

cos (x) (cos (2 x) - 2 sin^{2} (x))

4.5 \cdot 1 0^{9}

4 + \frac{5}{2}

\frac{81}{64}

- 3 x^{2} + 5 x - 2