What is 1/(k+6)+k/(k-8) ?

The solution to 1/(k+6)+k/(k-8) is (k^2+7k-8)/((k+6)(k-8))

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simplify 1/(k+6)+k/(k-8)

simplify

\frac{1}{k + 6} + \frac{k}{k - 8}

\frac{k ^{2} + 7 k - 8}{( k + 6 ) ( k - 8 )}

Solution steps

\frac{1}{k + 6} + \frac{k}{k - 8}

Least Common Multiplier of

k + 6, k - 8 : (k + 6) (k - 8)

Adjust Fractions based on the LCM

= \frac{k - 8}{( k + 6 ) ( k - 8 )} + \frac{k ( k + 6 )}{( k + 6 ) ( k - 8 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{k - 8 + k ( k + 6 )}{( k + 6 ) ( k - 8 )}

Simplify

k - 8 + k (k + 6) : k^{2} + 7 k - 8

= \frac{k ^{2} + 7 k - 8}{( k + 6 ) ( k - 8 )}

(2 + 3 i) (3 - 4 i)

(5 x + 4 y) (2 x + 5 y)

- 22 - 38 - 5

(- a^{3} + a^{2} - 2 a + 2) \cdot (a + 1)

What is 1/(k+6)+k/(k-8) ?
The solution to 1/(k+6)+k/(k-8) is (k^2+7k-8)/((k+6)(k-8))