What is (x^2+6x+8)/(x^2+3x-4) ?

The solution to (x^2+6x+8)/(x^2+3x-4) is (x+2)/(x-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x^2+6x+8)/(x^2+3x-4)

simplify

\frac{x ^{2} + 6 x + 8}{x ^{2} + 3 x - 4}

\frac{x + 2}{x - 1}

Solution steps

\frac{x ^{2} + 6 x + 8}{x ^{2} + 3 x - 4}

Factor

x^{2} + 6 x + 8 : (x + 2) (x + 4)

= \frac{( x + 2 ) ( x + 4 )}{x ^{2} + 3 x - 4}

Factor

x^{2} + 3 x - 4 : (x - 1) (x + 4)

= \frac{( x + 2 ) ( x + 4 )}{( x - 1 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x + 2}{x - 1}

- 2 (2 x + 1)

(x + 5) \cdot (x + 2)

2 y^{2} - y - 3

1 \frac{1}{3} \div 1 \frac{3}{4}

\frac{8}{7} + \frac{8}{7}

What is (x^2+6x+8)/(x^2+3x-4) ?
The solution to (x^2+6x+8)/(x^2+3x-4) is (x+2)/(x-1)