What are the solutions to the equation 25y^2=81 ?

The solutions to the equation 25y^2=81 are y= 9/5 ,y=-9/5

Find the zeros of 25y^2=81

The zeros of 25y^2=81 are y= 9/5 ,y=-9/5

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25 y^{2} = 81

y = \frac{9}{5}, y = - \frac{9}{5}

Solution steps

25 y^{2} = 81

Divide both sides by

25

y^{2} = \frac{81}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{81}{25}, y = - \frac{81}{25}

\frac{81}{25} = \frac{9}{5}

- \frac{81}{25} = - \frac{9}{5}

y = \frac{9}{5}, y = - \frac{9}{5}

x^{2} - 8 x - 84

\frac{1}{5} \cdot 40

\frac{3 i}{1 - 2 i}

3^{5}

5 s^{2} + 10 s + 500 = 0

What are the solutions to the equation 25y^2=81 ?
The solutions to the equation 25y^2=81 are y= 9/5 ,y=-9/5
Find the zeros of 25y^2=81
The zeros of 25y^2=81 are y= 9/5 ,y=-9/5