What are the solutions to the equation x^2+0.1x-0.2=0 ?

The solutions to the equation x^2+0.1x-0.2=0 are x= 2/5 ,x=-1/2

Find the zeros of x^2+0.1x-0.2=0

The zeros of x^2+0.1x-0.2=0 are x= 2/5 ,x=-1/2

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x^{2} + 0.1 x - 0.2 = 0

x = \frac{2}{5}, x = - \frac{1}{2}

Solution steps

x^{2} + 0.1 x - 0.2 = 0

Multiply both sides by

10

10 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 10 ( - 2 )}{2 \cdot 10}

1^{2} - 4 \cdot 10 (- 2) = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 \cdot 10}, x_{2} = \frac{- 1 - 9}{2 \cdot 10}

x = \frac{- 1 + 9}{2 \cdot 10} : \frac{2}{5}

x = \frac{- 1 - 9}{2 \cdot 10} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{1}{2}

\frac{25 !}{( 25 - 6 ) !}

98 - t^{2} = 0

(- 5 x^{4} y^{2})^{3}

\frac{d}{2} + 5 = 4 d + 2

2 x + 5 = x - 3

What are the solutions to the equation x^2+0.1x-0.2=0 ?
The solutions to the equation x^2+0.1x-0.2=0 are x= 2/5 ,x=-1/2
Find the zeros of x^2+0.1x-0.2=0
The zeros of x^2+0.1x-0.2=0 are x= 2/5 ,x=-1/2