What is (-2x^2y^3)^4(3.5x^0y) ?

The solution to (-2x^2y^3)^4(3.5x^0y) is 56x^8y^{13}

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simplify (-2x^2y^3)^4(3.5x^0y)

simplify

(- 2 x^{2} y^{3})^{4} (3.5 x^{0} y)

56 x^{8} y^{13}

Solution steps

(- 2 x^{2} y^{3})^{4} (3.5 x^{0} y)

Simplify

(- 2 x^{2} y^{3})^{4} : 16 x^{8} y^{12}

= 16 x^{8} y^{12} \cdot 3.5 x^{0} y

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

x^{0} = 1

= 16 x^{8} y^{12} \cdot 3.5 \cdot 1 \cdot y

Multiply the numbers:

16 \cdot 3.5 \cdot 1 = 56

= 56 x^{8} y^{12} y

Simplify

y^{12} y : y^{13}

= 56 x^{8} y^{13}

e^{l n (x) - x}

(h + 3)^{3}

\frac{1}{7} + \frac{2}{7}

\frac{x ^{2} - 81}{x - 3}

\frac{16}{9} + 1

What is (-2x^2y^3)^4(3.5x^0y) ?
The solution to (-2x^2y^3)^4(3.5x^0y) is 56x^8y^{13}