What is (8+3x-2x^2)-(4x^2+5x+3) ?

The solution to (8+3x-2x^2)-(4x^2+5x+3) is -6x^2-2x+5

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simplify (8+3x-2x^2)-(4x^2+5x+3)

simplify

(8 + 3 x - 2 x^{2}) - (4 x^{2} + 5 x + 3)

- 6 x^{2} - 2 x + 5

Solution steps

(8 + 3 x - 2 x^{2}) - (4 x^{2} + 5 x + 3)

Apply rule:

(a) = a

(8 + 3 x - 2 x^{2}) = 8 + 3 x - 2 x^{2}

= 8 + 3 x - 2 x^{2} - (4 x^{2} + 5 x + 3)

Apply the distributive law:

- (a + b) = - a - b

- (4 x^{2} + 5 x + 3) = - 4 x^{2} - 5 x - 3

= 8 + 3 x - 2 x^{2} - 4 x^{2} - 5 x - 3

Add similar elements:

- 2 x^{2} - 4 x^{2} = - 6 x^{2}

= 8 + 3 x - 6 x^{2} - 5 x - 3

Group like terms

= - 6 x^{2} + 3 x - 5 x + 8 - 3

Add similar elements:

3 x - 5 x = - 2 x

= - 6 x^{2} - 2 x + 8 - 3

Subtract the numbers:

8 - 3 = 5

= - 6 x^{2} - 2 x + 5

\frac{2}{\frac{5}{6}}

\frac{1}{2} \frac{3}{4}

2 (- 2 x - 2)^{2} - 5 (- 2 x - 2) + 15

\frac{1}{2} \cdot \frac{7}{3}

What is (8+3x-2x^2)-(4x^2+5x+3) ?
The solution to (8+3x-2x^2)-(4x^2+5x+3) is -6x^2-2x+5