What is (2x^2-3x+7)-(5x^2+3x+6) ?

The solution to (2x^2-3x+7)-(5x^2+3x+6) is -3x^2-6x+1

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simplify (2x^2-3x+7)-(5x^2+3x+6)

simplify

(2 x^{2} - 3 x + 7) - (5 x^{2} + 3 x + 6)

- 3 x^{2} - 6 x + 1

Solution steps

(2 x^{2} - 3 x + 7) - (5 x^{2} + 3 x + 6)

Apply rule:

(a) = a

(2 x^{2} - 3 x + 7) = 2 x^{2} - 3 x + 7

= 2 x^{2} - 3 x + 7 - (5 x^{2} + 3 x + 6)

Apply the distributive law:

- (a + b) = - a - b

- (5 x^{2} + 3 x + 6) = - 5 x^{2} - 3 x - 6

= 2 x^{2} - 3 x + 7 - 5 x^{2} - 3 x - 6

Group like terms

= 2 x^{2} - 5 x^{2} - 3 x - 3 x + 7 - 6

Add similar elements:

2 x^{2} - 5 x^{2} = - 3 x^{2}

= - 3 x^{2} - 3 x - 3 x + 7 - 6

Add similar elements:

- 3 x - 3 x = - 6 x

= - 3 x^{2} - 6 x + 7 - 6

Subtract the numbers:

7 - 6 = 1

= - 3 x^{2} - 6 x + 1

\frac{1}{7} \div \frac{7}{5}

\frac{9}{10} - \frac{1}{14}

\frac{3}{2} 3

\frac{2}{3} + \frac{8}{3}

1 \frac{3}{4} + \frac{2}{3}

What is (2x^2-3x+7)-(5x^2+3x+6) ?
The solution to (2x^2-3x+7)-(5x^2+3x+6) is -3x^2-6x+1