What is (b^2+6b+8)/(3b^2+12b) ?

The solution to (b^2+6b+8)/(3b^2+12b) is (b+2)/(3b)

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simplify (b^2+6b+8)/(3b^2+12b)

simplify

\frac{b ^{2} + 6 b + 8}{3 b ^{2} + 12 b}

\frac{b + 2}{3 b}

Solution steps

\frac{b ^{2} + 6 b + 8}{3 b ^{2} + 12 b}

Factor

b^{2} + 6 b + 8 : (b + 2) (b + 4)

= \frac{( b + 2 ) ( b + 4 )}{3 b ^{2} + 12 b}

Factor

3 b^{2} + 12 b : 3 b (b + 4)

= \frac{( b + 2 ) ( b + 4 )}{3 b ( b + 4 )}

Cancel the common factor:

b + 4

= \frac{b + 2}{3 b}

2 x (x - 1) - 4 (2 x + 3)

(a + bi) (a + bi)

(1 + \frac{3}{1 + i})^{2}

\frac{3 t ^{2}}{( 2 t ^{5} ) ^{2}}

7 (3 y - 5) + 2 (4 y + 3)

What is (b^2+6b+8)/(3b^2+12b) ?
The solution to (b^2+6b+8)/(3b^2+12b) is (b+2)/(3b)