What are the solutions to the equation 9m^2+5=-7m ?

The solutions to the equation 9m^2+5=-7m are m=-7/18+i(sqrt(131))/(18),m=-7/18-i(sqrt(131))/(18)

Find the zeros of 9m^2+5=-7m

The zeros of 9m^2+5=-7m are m=-7/18+i(sqrt(131))/(18),m=-7/18-i(sqrt(131))/(18)

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9 m^{2} + 5 = - 7 m

m = - \frac{7}{18} + i \frac{131}{18}, m = - \frac{7}{18} - i \frac{131}{18}

Solution steps

9 m^{2} + 5 = - 7 m

Move

7 m

to the left side

9 m^{2} + 5 + 7 m = 0

Write in the standard form

a x^{2} + b x + c = 0

9 m^{2} + 7 m + 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 9 \cdot 5}{2 \cdot 9}

Simplify

7^{2} - 4 \cdot 9 \cdot 5 : 131 i

m_{1, 2} = \frac{- 7 \pm 131 i}{2 \cdot 9}

Separate the solutions

m_{1} = \frac{- 7 + 131 i}{2 \cdot 9}, m_{2} = \frac{- 7 - 131 i}{2 \cdot 9}

m = \frac{- 7 + 131 i}{2 \cdot 9} : - \frac{7}{18} + i \frac{131}{18}

m = \frac{- 7 - 131 i}{2 \cdot 9} : - \frac{7}{18} - i \frac{131}{18}

The solutions to the quadratic equation are:

m = - \frac{7}{18} + i \frac{131}{18}, m = - \frac{7}{18} - i \frac{131}{18}

(\frac{4}{9})^{- 2}

2 0^{2} + b^{2} = 2 9^{2}

c - 12 > - 16

x^{2} - 7 x + 11 = 1

3 x^{2} - 3 x + 1 = 0

What are the solutions to the equation 9m^2+5=-7m ?
The solutions to the equation 9m^2+5=-7m are m=-7/18+i(sqrt(131))/(18),m=-7/18-i(sqrt(131))/(18)
Find the zeros of 9m^2+5=-7m
The zeros of 9m^2+5=-7m are m=-7/18+i(sqrt(131))/(18),m=-7/18-i(sqrt(131))/(18)