What is factor x^8+4x^6-4x^2-1 ?

The solution to factor x^8+4x^6-4x^2-1 is (x+1)(x-1)(x^2+1)(x^4+4x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor x^8+4x^6-4x^2-1

factor

x^{8} + 4 x^{6} - 4 x^{2} - 1

(x + 1) (x - 1) (x^{2} + 1) (x^{4} + 4 x^{2} + 1)

Solution steps

x^{8} + 4 x^{6} - 4 x^{2} - 1

Let

u = x^{2}

= u^{4} + 4 u^{3} - 4 u - 1

Factor

u^{4} + 4 u^{3} - 4 u - 1 : (u - 1) (u + 1) (u^{2} + 4 u + 1)

= (u - 1) (u + 1) (u^{2} + 4 u + 1)

Substitute back

u = x^{2}

= (x^{2} - 1) (x^{2} + 1) (x^{4} + 4 x^{2} + 1)

Factor

x^{2} - 1 : (x + 1) (x - 1)

= (x + 1) (x - 1) (x^{2} + 1) (x^{4} + 4 x^{2} + 1)

\frac{r ^{2}}{r ^{2}}

(5 - 3 i) + (- 2 + - 9)

- 2 \cdot (- 12)

2 \cdot \frac{1}{16}

- 3.46 + (- 4.23)

What is factor x^8+4x^6-4x^2-1 ?
The solution to factor x^8+4x^6-4x^2-1 is (x+1)(x-1)(x^2+1)(x^4+4x^2+1)