What are the solutions to the equation 5x^2-17x-40=0 ?

The solutions to the equation 5x^2-17x-40=0 are x=5,x=-8/5

Find the zeros of 5x^2-17x-40=0

The zeros of 5x^2-17x-40=0 are x=5,x=-8/5

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5 x^{2} - 17 x - 40 = 0

x = 5, x = - \frac{8}{5}

Solution steps

5 x^{2} - 17 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 5 ( - 40 )}{2 \cdot 5}

(- 17)^{2} - 4 \cdot 5 (- 40) = 33

x_{1, 2} = \frac{- ( - 17 ) \pm 33}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 33}{2 \cdot 5}, x_{2} = \frac{- ( - 17 ) - 33}{2 \cdot 5}

x = \frac{- ( - 17 ) + 33}{2 \cdot 5} : 5

x = \frac{- ( - 17 ) - 33}{2 \cdot 5} : - \frac{8}{5}

The solutions to the quadratic equation are:

x = 5, x = - \frac{8}{5}

3 x^{3} - x^{2} - 75 x + 25 < 0

x^{2} + 5 x + 4 < 0

5.1 (3 + 2.2 x) > - 14.25 - 6 (1.7 x + 4)

\frac{5 n}{2 15 n ^{4}}

7 x - 3 > - 10

What are the solutions to the equation 5x^2-17x-40=0 ?
The solutions to the equation 5x^2-17x-40=0 are x=5,x=-8/5
Find the zeros of 5x^2-17x-40=0
The zeros of 5x^2-17x-40=0 are x=5,x=-8/5