What is (x^3-2x+3)-(3x^2+4x-3) ?

The solution to (x^3-2x+3)-(3x^2+4x-3) is x^3-3x^2-6x+6

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simplify (x^3-2x+3)-(3x^2+4x-3)

simplify

(x^{3} - 2 x + 3) - (3 x^{2} + 4 x - 3)

x^{3} - 3 x^{2} - 6 x + 6

Solution steps

(x^{3} - 2 x + 3) - (3 x^{2} + 4 x - 3)

Apply rule:

(a) = a

(x^{3} - 2 x + 3) = x^{3} - 2 x + 3

= x^{3} - 2 x + 3 - (3 x^{2} + 4 x - 3)

Apply the distributive law:

- (a + b) = - a - b

- (3 x^{2} + 4 x - 3) = - 3 x^{2} - 4 x + 3

= x^{3} - 2 x + 3 - 3 x^{2} - 4 x + 3

Group like terms

= x^{3} - 3 x^{2} - 2 x - 4 x + 3 + 3

Add similar elements:

- 2 x - 4 x = - 6 x

= x^{3} - 3 x^{2} - 6 x + 3 + 3

Add the numbers:

3 + 3 = 6

= x^{3} - 3 x^{2} - 6 x + 6

2 x + 3 x^{- 1} - 5

81 a^{3} b

3 ab c - 2 a b^{2} c + 5 a^{2} b^{3} c^{2}

- 3 + 33

6 \div \frac{1}{\frac{1}{2}}

What is (x^3-2x+3)-(3x^2+4x-3) ?
The solution to (x^3-2x+3)-(3x^2+4x-3) is x^3-3x^2-6x+6