What is factor 1+729x^6 ?

The solution to factor 1+729x^6 is (9x^2+1)(81x^4-9x^2+1)

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factor 1+729x^6

factor

1 + 729 x^{6}

(9 x^{2} + 1) (81 x^{4} - 9 x^{2} + 1)

Solution steps

1 + 729 x^{6}

Write in the standard form

= 729 x^{6} + 1

Apply exponent rules

= (9 x^{2})^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(9 x^{2})^{3} + 1^{3} = (9 x^{2} + 1) (9^{2} x^{4} - 9 x^{2} + 1)

= (9 x^{2} + 1) (9^{2} x^{4} - 9 x^{2} + 1)

9^{2} = 81

= (9 x^{2} + 1) (81 x^{4} - 9 x^{2} + 1)

4 75 x^{5} y^{4}

2 x + [- 5 x - (- 2 y + (- x) + y)]

\frac{8.1 - 8}{8. 1 ^{2} - 9 ( 8.1 ) + 8}

(6 x^{- 2} y^{- 3})^{3}

- 6 (2 - 8 i) + 3 (5 + 7 i)

What is factor 1+729x^6 ?
The solution to factor 1+729x^6 is (9x^2+1)(81x^4-9x^2+1)