What is expand (4x^2+5x+4)(x^2-3x+1) ?

The solution to expand (4x^2+5x+4)(x^2-3x+1) is 4x^4-7x^3-7x^2-7x+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x^2+5x+4)(x^2-3x+1)

expand

(4 x^{2} + 5 x + 4) (x^{2} - 3 x + 1)

4 x^{4} - 7 x^{3} - 7 x^{2} - 7 x + 4

Solution steps

(4 x^{2} + 5 x + 4) (x^{2} - 3 x + 1)

Distribute parentheses

= 4 x^{2} x^{2} + 4 x^{2} (- 3 x) + 4 x^{2} \cdot 1 + 5 x x^{2} + 5 x (- 3 x) + 5 x \cdot 1 + 4 x^{2} + 4 (- 3 x) + 4 \cdot 1

Simplify

4 x^{2} x^{2} + 4 x^{2} (- 3 x) + 4 x^{2} \cdot 1 + 5 x x^{2} + 5 x (- 3 x) + 5 x \cdot 1 + 4 x^{2} + 4 (- 3 x) + 4 \cdot 1 : 4 x^{4} - 7 x^{3} - 7 x^{2} - 7 x + 4

= 4 x^{4} - 7 x^{3} - 7 x^{2} - 7 x + 4

\frac{- 48}{- 8}

\frac{5}{8} \cdot 6

(x)^{- 2}

\frac{5}{8} \cdot 3

- 3 \cdot 2 x

What is expand (4x^2+5x+4)(x^2-3x+1) ?
The solution to expand (4x^2+5x+4)(x^2-3x+1) is 4x^4-7x^3-7x^2-7x+4