What is (5-x)/(x^2+2x-35) ?

The solution to (5-x)/(x^2+2x-35) is -1/(x+7)

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simplify (5-x)/(x^2+2x-35)

simplify

\frac{5 - x}{x ^{2} + 2 x - 35}

- \frac{1}{x + 7}

Solution steps

\frac{5 - x}{x ^{2} + 2 x - 35}

Factor

x^{2} + 2 x - 35 : (x - 5) (x + 7)

= \frac{5 - x}{( x - 5 ) ( x + 7 )}

5 - x = - (x - 5)

= \frac{- ( x - 5 )}{( x - 5 ) ( x + 7 )}

Cancel the common factor:

x - 5

= \frac{- 1}{x + 7}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{1}{x + 7}

lo g_{5} (5^{\frac{13}{2}})

ln (ln (e^{e^{4}}))

t^{2} \cdot u \cdot (t - 4)

2 x + 24

(2 x^{2} y + 4 m)^{2}