What is (4-3i)/(3+2i) ?

The solution to (4-3i)/(3+2i) is 6/13-17/13 i

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simplify (4-3i)/(3+2i)

simplify

\frac{4 - 3 i}{3 + 2 i}

\frac{6}{13} - \frac{17}{13} i

Solution steps

\frac{4 - 3 i}{3 + 2 i}

Multiply by the conjugate

\frac{3 - 2 i}{3 - 2 i}

= \frac{( 4 - 3 i ) ( 3 - 2 i )}{( 3 + 2 i ) ( 3 - 2 i )}

Simplify

\frac{( 4 - 3 i ) ( 3 - 2 i )}{( 3 + 2 i ) ( 3 - 2 i )} : \frac{6 - 17 i}{13}

= \frac{6 - 17 i}{13}

Rewrite in standard complex form:

\frac{6}{13} - \frac{17}{13} i

= \frac{6}{13} - \frac{17}{13} i

3 \frac{3}{10} \div 1 \frac{4}{7}

(- 32)^{2}

\frac{3 ( x - 2 )}{- ( 2 - x )}

(- \frac{27}{64})^{\frac{4}{3}}

x^{3} - 1^{3}