What is (5x^2-3x+4)+(6x-3x^2-3) ?

The solution to (5x^2-3x+4)+(6x-3x^2-3) is 2x^2+3x+1

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simplify (5x^2-3x+4)+(6x-3x^2-3)

simplify

(5 x^{2} - 3 x + 4) + (6 x - 3 x^{2} - 3)

2 x^{2} + 3 x + 1

Solution steps

(5 x^{2} - 3 x + 4) + (6 x - 3 x^{2} - 3)

Simplify

(5 x^{2} - 3 x + 4) + (6 x - 3 x^{2} - 3) : 5 x^{2} - 3 x + 4 + 6 x - 3 x^{2} - 3

= 5 x^{2} - 3 x + 4 + 6 x - 3 x^{2} - 3

Group like terms

= 5 x^{2} - 3 x^{2} - 3 x + 6 x + 4 - 3

Add similar elements:

5 x^{2} - 3 x^{2} = 2 x^{2}

= 2 x^{2} - 3 x + 6 x + 4 - 3

Add similar elements:

- 3 x + 6 x = 3 x

= 2 x^{2} + 3 x + 4 - 3

Subtract the numbers:

4 - 3 = 1

= 2 x^{2} + 3 x + 1

cos (θ) \cdot cos (θ)

21 + 20 i + - 12 - 16 i

\frac{3}{10} + (- \frac{5}{6})

\frac{6 x ^{2} y ^{3}}{3 x y ^{5}}

5 (- 9)

What is (5x^2-3x+4)+(6x-3x^2-3) ?
The solution to (5x^2-3x+4)+(6x-3x^2-3) is 2x^2+3x+1