What is (3+4i)+(-1-6i) ?

The solution to (3+4i)+(-1-6i) is 2-2i

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simplify (3+4i)+(-1-6i)

simplify

(3 + 4 i) + (- 1 - 6 i)

2 - 2 i

Solution steps

(3 + 4 i) + (- 1 - 6 i)

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= (3 - 1) + (4 - 6) i

Simplify

(3 - 1) + (4 - 6) i : 2 - 2 i

= 2 - 2 i

1 m

20 \cdot (- 2)

\frac{45}{81}

3 (a - b)^{2} - 2 (a - b)^{2}

- 1 (x - 1)