What is ((2-x)(x^2+x+1))/((5-x))>0 ?

The solution to ((2-x)(x^2+x+1))/((5-x))>0 is x 5

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((2-x)(x^2+x+1))/((5-x))>0

\frac{( 2 - x ) ( x ^{2} + x + 1 )}{( 5 - x )} > 0

x < 2 or x > 5

Interval Notation

(- \infty, 2) \cup (5, \infty)

Solution steps

\frac{( 2 - x ) ( x ^{2} + x + 1 )}{5 - x} > 0

Identify the intervals

x < 2 or x > 5

3 (2 - 24)

- 6 m^{2} + 18 m - 36

\frac{1}{2} x - 6 = 5

(- 3 + 2 i) (7 + 3 i)

- \frac{9}{3}

What is ((2-x)(x^2+x+1))/((5-x))>0 ?
The solution to ((2-x)(x^2+x+1))/((5-x))>0 is x<2\lor x>5