What is factor 2m^5+12m^4+18m^3 ?

The solution to factor 2m^5+12m^4+18m^3 is 2m^3(m+3)^2

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factor 2m^5+12m^4+18m^3

factor

2 m^{5} + 12 m^{4} + 18 m^{3}

2 m^{3} (m + 3)^{2}

Solution steps

2 m^{5} + 12 m^{4} + 18 m^{3}

Factor out common term

2 m^{3} : 2 m^{3} (m^{2} + 6 m + 9)

= 2 m^{3} (m^{2} + 6 m + 9)

Factor

m^{2} + 6 m + 9 : (m + 3) (m + 3)

= 2 m^{3} (m + 3) (m + 3)

Apply exponent rule:

aa = a^{2}

(m + 3) (m + 3) = (m + 3)^{2}

= 2 m^{3} (m + 3)^{2}

(4 x^{2} + x - 2) (x^{2} + x + 2)

(- 3 y)^{2}

36.4 + (- 68.15)

sin (3 x) \cdot cos (3 x)

2 x (3 x^{2} - 5 x - 3)

What is factor 2m^5+12m^4+18m^3 ?
The solution to factor 2m^5+12m^4+18m^3 is 2m^3(m+3)^2