What is 1/(\sqrt[4]{x^2-9x)} ?

The solution to 1/(\sqrt[4]{x^2-9x)} is ((x^2-9x)^{3/4})/(x^2-9x)

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simplify 1/(\sqrt[4]{x^2-9x)}

simplify

\frac{( x ^{2} - 9 x ) ^{\frac{3}{4}}}{x ^{2} - 9 x}

Solution steps

Multiply by the conjugate

\frac{( x ^{2} - 9 x ) ^{\frac{3}{4}}}{( x ^{2} - 9 x ) ^{\frac{3}{4}}}

1 \cdot (x^{2} - 9 x)^{\frac{3}{4}} = (x^{2} - 9 x)^{\frac{3}{4}}

= \frac{( x ^{2} - 9 x ) ^{\frac{3}{4}}}{x ^{2} - 9 x}

(x + 4)^{2} + 5 (x + 4)

- 20 + 7

(8^{3})^{\frac{1}{5}}

13 \frac{1}{2}

- 5 x^{2} + x + 4

What is 1/(\sqrt[4]{x^2-9x)} ?
The solution to 1/(\sqrt[4]{x^2-9x)} is ((x^2-9x)^{3/4})/(x^2-9x)