What are the solutions to the equation x^2+5x+3=0 ?

The solutions to the equation x^2+5x+3=0 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2

Find the zeros of x^2+5x+3=0

The zeros of x^2+5x+3=0 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2

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x^{2} + 5 x + 3 = 0

x = \frac{- 5 + 13}{2}, x = \frac{- 5 - 13}{2}

Decimal Notation

x = - 0.69722 \dots, x = - 4.30277 \dots

Solution steps

x^{2} + 5 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 3 = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 1}, x_{2} = \frac{- 5 - 13}{2 \cdot 1}

x = \frac{- 5 + 13}{2 \cdot 1} : \frac{- 5 + 13}{2}

x = \frac{- 5 - 13}{2 \cdot 1} : \frac{- 5 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 13}{2}, x = \frac{- 5 - 13}{2}

(- 7 x)^{\frac{1}{5}}

9 e + 4 = - 5 e + 14 + 13 e

8 x + 10 - 2 x = 4 (x - 5)

(\frac{x}{x})^{2}

\frac{10}{3} = \frac{k}{9}

What are the solutions to the equation x^2+5x+3=0 ?
The solutions to the equation x^2+5x+3=0 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2
Find the zeros of x^2+5x+3=0
The zeros of x^2+5x+3=0 are x=(-5+sqrt(13))/2 ,x=(-5-sqrt(13))/2