What is (m+n-1)x^2+(m+n-1)x-(m+n-1) ?

The solution to (m+n-1)x^2+(m+n-1)x-(m+n-1) is (m+n-1)x^2+(m+n-1)x-m-n+1

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simplify (m+n-1)x^2+(m+n-1)x-(m+n-1)

simplify

(m + n - 1) x^{2} + (m + n - 1) x - (m + n - 1)

(m + n - 1) x^{2} + (m + n - 1) x - m - n + 1

Solution steps

(m + n - 1) x^{2} + (m + n - 1) x - (m + n - 1)

Apply the distributive law:

- (a + b) = - a - b

- (m + n - 1) = - m - n + 1

= (m + n - 1) x^{2} + (m + n - 1) x - m - n + 1

2 a + 2

3 \cdot 100

(\frac{1}{27})^{\frac{- 2}{3}}

(2 t - 2)^{2}

What is (m+n-1)x^2+(m+n-1)x-(m+n-1) ?
The solution to (m+n-1)x^2+(m+n-1)x-(m+n-1) is (m+n-1)x^2+(m+n-1)x-m-n+1