What is factor 1-d^{12} ?

The solution to factor 1-d^{12} is -(d^2+1)(d+1)(d-1)(d^2+d+1)(d^2-d+1)(d^4-d^2+1)

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factor 1-d^{12}

factor

1 - d^{12}

- (d^{2} + 1) (d + 1) (d - 1) (d^{2} + d + 1) (d^{2} - d + 1) (d^{4} - d^{2} + 1)

Solution steps

1 - d^{12}

Write in the standard form

= - d^{12} + 1

Factor out

- 1 : - (d^{12} - 1)

= - (d^{12} - 1)

Factor

d^{12} - 1 : (d^{2} + 1) (d + 1) (d - 1) (d^{2} + 1 + d) (d^{2} + 1 - d) (d^{4} + 1 - d^{2})

= - (d^{2} + 1) (d + 1) (d - 1) (d^{2} + 1 + d) (d^{2} + 1 - d) (d^{4} + 1 - d^{2})

= - (d^{2} + 1) (d + 1) (d - 1) (d^{2} + d + 1) (d^{2} - d + 1) (d^{4} - d^{2} + 1)

\frac{56}{77}

π - \frac{22}{7}

x (\frac{x}{2})

\frac{- 125}{216}

37 \cdot 535

What is factor 1-d^{12} ?
The solution to factor 1-d^{12} is -(d^2+1)(d+1)(d-1)(d^2+d+1)(d^2-d+1)(d^4-d^2+1)