What is (8x^3-1)/(4x^2-1) ?

The solution to (8x^3-1)/(4x^2-1) is (4x^2+2x+1)/(2x+1)

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simplify (8x^3-1)/(4x^2-1)

simplify

\frac{8 x ^{3} - 1}{4 x ^{2} - 1}

\frac{4 x ^{2} + 2 x + 1}{2 x + 1}

Solution steps

\frac{8 x ^{3} - 1}{4 x ^{2} - 1}

Factor

8 x^{3} - 1 : (2 x - 1) (4 x^{2} + 2 x + 1)

= \frac{( 2 x - 1 ) ( 4 x ^{2} + 2 x + 1 )}{4 x ^{2} - 1}

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= \frac{( 2 x - 1 ) ( 4 x ^{2} + 2 x + 1 )}{( 2 x + 1 ) ( 2 x - 1 )}

Cancel the common factor:

2 x - 1

= \frac{4 x ^{2} + 2 x + 1}{2 x + 1}

9604

- 8 + v - 2 v

\frac{b}{2 b + 1} - \frac{2 b}{b - 2}

(6^{- 1})^{- 2}

(5 x - 3) (25 x^{2} + 15 x + 9)

What is (8x^3-1)/(4x^2-1) ?
The solution to (8x^3-1)/(4x^2-1) is (4x^2+2x+1)/(2x+1)