What are the solutions to the equation x^2+8x+2=0 ?

The solutions to the equation x^2+8x+2=0 are x=-4+sqrt(14),x=-4-sqrt(14)

Find the zeros of x^2+8x+2=0

The zeros of x^2+8x+2=0 are x=-4+sqrt(14),x=-4-sqrt(14)

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x^{2} + 8 x + 2 = 0

x = - 4 + 14, x = - 4 - 14

Solution steps

x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 2 = 214

x_{1, 2} = \frac{- 8 \pm 2 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 14}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 14}{2 \cdot 1}

x = \frac{- 8 + 2 14}{2 \cdot 1} : - 4 + 14

x = \frac{- 8 - 2 14}{2 \cdot 1} : - 4 - 14

The solutions to the quadratic equation are:

x = - 4 + 14, x = - 4 - 14

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What are the solutions to the equation x^2+8x+2=0 ?
The solutions to the equation x^2+8x+2=0 are x=-4+sqrt(14),x=-4-sqrt(14)
Find the zeros of x^2+8x+2=0
The zeros of x^2+8x+2=0 are x=-4+sqrt(14),x=-4-sqrt(14)