What is ((2j^3p)^{-1})/(10j^6) ?

The solution to ((2j^3p)^{-1})/(10j^6) is 1/(20j^9p)

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simplify ((2j^3p)^{-1})/(10j^6)

simplify

\frac{( 2 j ^{3} p ) ^{- 1}}{10 j ^{6}}

\frac{1}{20 j ^{9} p}

Solution steps

\frac{( 2 j ^{3} p ) ^{- 1}}{10 j ^{6}}

Simplify

(2 j^{3} p)^{- 1} : 2^{- 1} \cdot \frac{1}{j ^{3}} p^{- 1}

= \frac{2 ^{- 1} \cdot \frac{1}{j ^{3}} p ^{- 1}}{10 j ^{6}}

Factor the number:

10 = 2 \cdot 5

= \frac{2 ^{- 1} \cdot \frac{1}{j ^{3}} p ^{- 1}}{2 \cdot 5 j ^{6}}

\frac{2 ^{- 1}}{2} = \frac{1}{2 ^{2}}

= \frac{\frac{1}{j ^{3}} p ^{- 1}}{2 ^{2} \cdot 5 j ^{6}}

Simplify

\frac{\frac{1}{j ^{3}} p ^{- 1}}{2 ^{2} \cdot 5 j ^{6}} : \frac{1}{j ^{9} p \cdot 20}

= \frac{1}{j ^{9} p \cdot 20}

= \frac{1}{20 j ^{9} p}

\frac{2}{2} + \frac{2}{3}

\frac{84}{- 12}

\frac{9}{9 + i}

6^{2} - 5^{2}

What is ((2j^3p)^{-1})/(10j^6) ?
The solution to ((2j^3p)^{-1})/(10j^6) is 1/(20j^9p)