What is factor 4r^2+20r+25 ?

The solution to factor 4r^2+20r+25 is (2r+5)^2

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factor 4r^2+20r+25

factor

4 r^{2} + 20 r + 25

(2 r + 5)^{2}

Solution steps

4 r^{2} + 20 r + 25

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 r^{2} = (2 r)^{2}

25 = 5^{2}

20 r = 2 \cdot 2 r \cdot 5

= (2 r)^{2} + 2 \cdot 2 r \cdot 5 + 5^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(2 r)^{2} + 2 \cdot 2 r \cdot 5 + 5^{2} = (2 r + 5)^{2}

= (2 r + 5)^{2}

2 + \frac{3}{8}

\frac{a x - a y}{3 a}

(3) (5)

7 x^{2} + 19 x + 10

(m + n - p) + (- m - n + p)