What are the solutions to the equation -16x^2+64x+80=0 ?

The solutions to the equation -16x^2+64x+80=0 are x=-1,x=5

Find the zeros of -16x^2+64x+80=0

The zeros of -16x^2+64x+80=0 are x=-1,x=5

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- 16 x^{2} + 64 x + 80 = 0

x = - 1, x = 5

Solution steps

- 16 x^{2} + 64 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 80}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 80 = 96

x_{1, 2} = \frac{- 64 \pm 96}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 64 + 96}{2 ( - 16 )}, x_{2} = \frac{- 64 - 96}{2 ( - 16 )}

x = \frac{- 64 + 96}{2 ( - 16 )} : - 1

x = \frac{- 64 - 96}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

x = - 1, x = 5

0 = - x - 3

\frac{x}{x + 2} + \frac{1}{x - 1} < \frac{3}{2}

8 a^{2} b^{3} - 4 a^{2} b^{2}

x^{2} - 10 x + 41 = 0

2 (y + 1) + 4 y = 3 (2 y - 1) + 8

What are the solutions to the equation -16x^2+64x+80=0 ?
The solutions to the equation -16x^2+64x+80=0 are x=-1,x=5
Find the zeros of -16x^2+64x+80=0
The zeros of -16x^2+64x+80=0 are x=-1,x=5