What is factor 49y^4-81x^6 ?

The solution to factor 49y^4-81x^6 is (7y^2+9x^3)(7y^2-9x^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 49y^4-81x^6

factor

49 y^{4} - 81 x^{6}

(7 y^{2} + 9 x^{3}) (7 y^{2} - 9 x^{3})

Solution steps

49 y^{4} - 81 x^{6}

49 y^{4} = (7 y^{2})^{2}

81 x^{6} = (9 x^{3})^{2}

= (7 y^{2})^{2} - (9 x^{3})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(7 y^{2})^{2} - (9 x^{3})^{2} = (7 y^{2} + 9 x^{3}) (7 y^{2} - 9 x^{3})

= (7 y^{2} + 9 x^{3}) (7 y^{2} - 9 x^{3})

(y - 6)^{3}

\frac{20}{26}

\frac{2 5}{2}

(\frac{9}{6} t - 4) 2

- 3.2 + 8.6 - 2.4

What is factor 49y^4-81x^6 ?
The solution to factor 49y^4-81x^6 is (7y^2+9x^3)(7y^2-9x^3)