What is (7x^{-3}y^{-8})(2x^5y^5) ?

The solution to (7x^{-3}y^{-8})(2x^5y^5) is (14x^2)/(y^3)

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simplify (7x^{-3}y^{-8})(2x^5y^5)

simplify

(7 x^{- 3} y^{- 8}) (2 x^{5} y^{5})

\frac{14 x ^{2}}{y ^{3}}

Solution steps

(7 x^{- 3} y^{- 8}) (2 x^{5} y^{5})

Simplify

7 x^{- 3} y^{- 8} : \frac{7}{x ^{3} y ^{8}}

= \frac{7}{x ^{3} y ^{8}} \cdot 2 x^{5} y^{5}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{7 \cdot 2 x ^{5} y ^{5}}{x ^{3} y ^{8}}

Simplify

\frac{x ^{5}}{x ^{3}} : x^{2}

= \frac{7 \cdot 2 x ^{2} y ^{5}}{y ^{8}}

Simplify

\frac{y ^{5}}{y ^{8}} : \frac{1}{y ^{3}}

= \frac{7 \cdot 2 x ^{2}}{y ^{3}}

Multiply the numbers:

7 \cdot 2 = 14

= \frac{14 x ^{2}}{y ^{3}}

lo g_{10} (2) (3)

4 x^{2} (x^{3} - x + 2)

12 x^{7} y^{2}

- (\frac{9}{2})^{2}

4 a - 7.5 b + 9 b - 2.1 a

What is (7x^{-3}y^{-8})(2x^5y^5) ?
The solution to (7x^{-3}y^{-8})(2x^5y^5) is (14x^2)/(y^3)