What is ((2+i)(1-i))/(4-3i) ?

The solution to ((2+i)(1-i))/(4-3i) is 3/5+1/5 i

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simplify ((2+i)(1-i))/(4-3i)

simplify

\frac{( 2 + i ) ( 1 - i )}{4 - 3 i}

\frac{3}{5} + \frac{1}{5} i

Solution steps

\frac{( 2 + i ) ( 1 - i )}{4 - 3 i}

Multiply by the conjugate

\frac{4 + 3 i}{4 + 3 i}

= \frac{( 2 + i ) ( 1 - i ) ( 4 + 3 i )}{( 4 - 3 i ) ( 4 + 3 i )}

Simplify

\frac{( 2 + i ) ( 1 - i ) ( 4 + 3 i )}{( 4 - 3 i ) ( 4 + 3 i )} : \frac{15 + 5 i}{25}

= \frac{15 + 5 i}{25}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{15}{25} + \frac{5}{25} i

Simplify

\frac{15}{25} + \frac{5}{25} i : \frac{3}{5} + \frac{1}{5} i

= \frac{3}{5} + \frac{1}{5} i

7 y^{0}

(0. 1^{2} + 1)^{\frac{3}{2}}

\frac{1}{6} \cdot (- 3)

10 \cdot (- \frac{1}{2})

- (- 6.2 k - 1)