What is the answer to (3x-2)/4-(2x-5)/3 =(1+x)/6 ?

The answer to (3x-2)/4-(2x-5)/3 =(1+x)/6 is x=12

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(3x-2)/4-(2x-5)/3 =(1+x)/6

\frac{3 x - 2}{4} - \frac{2 x - 5}{3} = \frac{1 + x}{6}

x = 12

Solution steps

\frac{3 x - 2}{4} - \frac{2 x - 5}{3} = \frac{1 + x}{6}

Multiply by LCM

3 (3 x - 2) - 4 (2 x - 5) = 2 (x + 1)

Expand

3 (3 x - 2) - 4 (2 x - 5) : x + 14

Expand

2 (x + 1) : 2 x + 2

x + 14 = 2 x + 2

Move

14

to the right side

x = 2 x - 12

Move

2 x

to the left side

- x = - 12

Divide both sides by

- 1

x = 12

3 (- 2 x + 1) - 2 (x + 13) = 7 x - 4 (1 - x)

- 7 < 3 x + 2 \leq 19

x^{2} - 10 = 62

(5 v^{4})^{2} \cdot 2 v^{3} \cdot v

\frac{1.75 \cdot 61 + 0}{1.75 + 1}

What is the answer to (3x-2)/4-(2x-5)/3 =(1+x)/6 ?
The answer to (3x-2)/4-(2x-5)/3 =(1+x)/6 is x=12
Solve for x: (3x-2)/4-(2x-5)/3 =(1+x)/6
The solution is x=12