What is (7-3i)/(4-8i) ?

The solution to (7-3i)/(4-8i) is 13/20+11/20 i

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simplify (7-3i)/(4-8i)

simplify

\frac{7 - 3 i}{4 - 8 i}

\frac{13}{20} + \frac{11}{20} i

Solution steps

\frac{7 - 3 i}{4 - 8 i}

Multiply by the conjugate

\frac{4 + 8 i}{4 + 8 i}

= \frac{( 7 - 3 i ) ( 4 + 8 i )}{( 4 - 8 i ) ( 4 + 8 i )}

Simplify

\frac{( 7 - 3 i ) ( 4 + 8 i )}{( 4 - 8 i ) ( 4 + 8 i )} : \frac{52 + 44 i}{80}

= \frac{52 + 44 i}{80}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{52}{80} + \frac{44}{80} i

Simplify

\frac{52}{80} + \frac{44}{80} i : \frac{13}{20} + \frac{11}{20} i

= \frac{13}{20} + \frac{11}{20} i

(- 4) (- 5)

C O^{2} + H^{2} O

2^{x} + 2^{x + 1}

3 \cdot 22

3 \cdot 23