What are the solutions to the equation r^2-8r+25=0 ?

The solutions to the equation r^2-8r+25=0 are r=4+3i,r=4-3i

Find the zeros of r^2-8r+25=0

The zeros of r^2-8r+25=0 are r=4+3i,r=4-3i

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r^{2} - 8 r + 25 = 0

r = 4 + 3 i, r = 4 - 3 i

Solution steps

r^{2} - 8 r + 25 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 25 : 6 i

r_{1, 2} = \frac{- ( - 8 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 6 i}{2 \cdot 1}, r_{2} = \frac{- ( - 8 ) - 6 i}{2 \cdot 1}

r = \frac{- ( - 8 ) + 6 i}{2 \cdot 1} : 4 + 3 i

r = \frac{- ( - 8 ) - 6 i}{2 \cdot 1} : 4 - 3 i

The solutions to the quadratic equation are:

r = 4 + 3 i, r = 4 - 3 i

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9 x - 7 < 38

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6 x^{4} y^{3} + 3 x^{8} y^{6}

What are the solutions to the equation r^2-8r+25=0 ?
The solutions to the equation r^2-8r+25=0 are r=4+3i,r=4-3i
Find the zeros of r^2-8r+25=0
The zeros of r^2-8r+25=0 are r=4+3i,r=4-3i