What is expand (x+2)(2x+1)(4x-5) ?

The solution to expand (x+2)(2x+1)(4x-5) is 8x^3+10x^2-17x-10

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expand (x+2)(2x+1)(4x-5)

expand

(x + 2) (2 x + 1) (4 x - 5)

8 x^{3} + 10 x^{2} - 17 x - 10

Solution steps

(x + 2) (2 x + 1) (4 x - 5)

Expand

(x + 2) (2 x + 1) (4 x - 5) : (2 x^{2} + 5 x + 2) (4 x - 5)

= (2 x^{2} + 5 x + 2) (4 x - 5)

Distribute parentheses

= 2 x^{2} \cdot 4 x + 2 x^{2} (- 5) + 5 x \cdot 4 x + 5 x (- 5) + 2 \cdot 4 x + 2 (- 5)

Simplify

2 x^{2} \cdot 4 x + 2 x^{2} (- 5) + 5 x \cdot 4 x + 5 x (- 5) + 2 \cdot 4 x + 2 (- 5) : 8 x^{3} + 10 x^{2} - 17 x - 10

= 8 x^{3} + 10 x^{2} - 17 x - 10

(3 x^{5} y^{- 7})^{2}

2 x (5 x + 2) - (2 x + 1) (x - 1) + (x + 3)^{2}

- x (3 x - 4 y) - 2 x y (3 x - 4 y) + 4 y (4 y - 3 x)

(w^{0} x^{5})^{- 1}

(2 x + 4)^{4}

What is expand (x+2)(2x+1)(4x-5) ?
The solution to expand (x+2)(2x+1)(4x-5) is 8x^3+10x^2-17x-10